[mixcloud] Simplify url extraction

On the tracks I tested the server number in the url from the webpage is valid
for the mp3 or the m4a file and any other number is invalid, it's a
waste of time to check them.
master
Jaime Marquínez Ferrándiz 2015-04-17 19:02:49 +02:00
parent d8e7ef04dc
commit c5826a491b
1 changed files with 15 additions and 57 deletions

View File

@ -1,7 +1,6 @@
from __future__ import unicode_literals
import re
import itertools
from .common import InfoExtractor
from ..compat import (
@ -46,20 +45,16 @@ class MixcloudIE(InfoExtractor):
},
}]
def _get_url(self, track_id, template_url, server_number):
boundaries = (1, 30)
for nr in server_numbers(server_number, boundaries):
url = template_url % nr
def _check_url(self, url, track_id, ext):
try:
# We only want to know if the request succeed
# don't download the whole file
self._request_webpage(
HEADRequest(url), track_id,
'Checking URL %d/%d ...' % (nr, boundaries[-1]))
return url
'Trying %s URL' % ext)
return True
except ExtractorError:
pass
return None
return False
def _real_extract(self, url):
mobj = re.match(self._VALID_URL, url)
@ -72,14 +67,9 @@ class MixcloudIE(InfoExtractor):
preview_url = self._search_regex(
r'\s(?:data-preview-url|m-preview)="([^"]+)"', webpage, 'preview url')
song_url = preview_url.replace('/previews/', '/c/originals/')
server_number = int(self._search_regex(r'stream(\d+)', song_url, 'server number'))
template_url = re.sub(r'(stream\d*)', 'stream%d', song_url)
final_song_url = self._get_url(track_id, template_url, server_number)
if final_song_url is None:
self.to_screen('Trying with m4a extension')
template_url = template_url.replace('.mp3', '.m4a').replace('originals/', 'm4a/64/')
final_song_url = self._get_url(track_id, template_url, server_number)
if final_song_url is None:
if not self._check_url(song_url, track_id, 'mp3'):
song_url = song_url.replace('.mp3', '.m4a').replace('originals/', 'm4a/64/')
if not self._check_url(song_url, track_id, 'm4a'):
raise ExtractorError('Unable to extract track url')
PREFIX = (
@ -107,7 +97,7 @@ class MixcloudIE(InfoExtractor):
return {
'id': track_id,
'title': title,
'url': final_song_url,
'url': song_url,
'description': description,
'thumbnail': thumbnail,
'uploader': uploader,
@ -115,35 +105,3 @@ class MixcloudIE(InfoExtractor):
'view_count': view_count,
'like_count': like_count,
}
def server_numbers(first, boundaries):
""" Server numbers to try in descending order of probable availability.
Starting from first (i.e. the number of the server hosting the preview file)
and going further and further up to the higher boundary and down to the
lower one in an alternating fashion. Namely:
server_numbers(2, (1, 5))
# Where the preview server is 2, min number is 1 and max is 5.
# Yields: 2, 3, 1, 4, 5
Why not random numbers or increasing sequences? Since from what I've seen,
full length files seem to be hosted on servers whose number is closer to
that of the preview; to be confirmed.
"""
zip_longest = getattr(itertools, 'zip_longest', None)
if zip_longest is None:
# python 2.x
zip_longest = itertools.izip_longest
if len(boundaries) != 2:
raise ValueError("boundaries should be a two-element tuple")
min, max = boundaries
highs = range(first + 1, max + 1)
lows = range(first - 1, min - 1, -1)
rest = filter(
None, itertools.chain.from_iterable(zip_longest(highs, lows)))
yield first
for n in rest:
yield n