5 lines
347 B
SQL
5 lines
347 B
SQL
SELECT DISTINCTROW [Function Types].[Function Type],
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Functions.[Function Name],
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[Research Upgrade Function].[Research Points]
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FROM [Function Types] INNER JOIN (Functions INNER JOIN [Research Upgrade Function] ON Functions.[Function ID] = [Research Upgrade Function].[Function ID]) ON [Function Types].ID = Functions.[Function Type];
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