58 lines
2.0 KiB
Python
58 lines
2.0 KiB
Python
#!/usr/bin/env python
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# This Source Code Form is subject to the terms of the Mozilla Public
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# License, v. 2.0. If a copy of the MPL was not distributed with this
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# file, You can obtain one at http://mozilla.org/MPL/2.0/.
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# Usage: check_source_count.py SEARCH_TERM COUNT ERROR_LOCATION REPLACEMENT [FILES...]
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# Checks that FILES contains exactly COUNT matches of SEARCH_TERM. If it does
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# not, an error message is printed, quoting ERROR_LOCATION, which should
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# probably be the filename and line number of the erroneous call to
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# check_source_count.py.
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from __future__ import print_function
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import sys
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import os
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import re
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search_string = sys.argv[1]
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expected_count = int(sys.argv[2])
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error_location = sys.argv[3]
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replacement = sys.argv[4]
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files = sys.argv[5:]
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details = {}
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count = 0
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for f in files:
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text = file(f).read()
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match = re.findall(search_string, text)
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if match:
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num = len(match)
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count += num
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details[f] = num
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if count == expected_count:
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print("TEST-PASS | check_source_count.py {0} | {1}"
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.format(search_string, expected_count))
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else:
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print("TEST-UNEXPECTED-FAIL | check_source_count.py {0} | "
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.format(search_string),
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end='')
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if count < expected_count:
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print("There are fewer occurrences of /{0}/ than expected. "
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"This may mean that you have removed some, but forgotten to "
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"account for it {1}.".format(search_string, error_location))
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else:
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print("There are more occurrences of /{0}/ than expected. We're trying "
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"to prevent an increase in the number of {1}'s, using {2} if "
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"possible. If it is unavoidable, you should update the expected "
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"count {3}.".format(search_string, search_string, replacement,
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error_location))
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print("Expected: {0}; found: {1}".format(expected_count, count))
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for k in sorted(details):
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print("Found {0} occurences in {1}".format(details[k],k))
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sys.exit(-1)
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