ocaml/test/Moretest/fftba.ml

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(***********************************************************************)
(* *)
(* Objective Caml *)
(* *)
(* Xavier Leroy, projet Cristal, INRIA Rocquencourt *)
(* *)
(* Copyright 1996 Institut National de Recherche en Informatique et *)
(* en Automatique. All rights reserved. This file is distributed *)
(* under the terms of the Q Public License version 1.0. *)
(* *)
(***********************************************************************)
(* $Id$ *)
open Bigarray
let pi = 3.14159265358979323846
let tpi = 2.0 *. pi
let fft (px : (float, float64_elt, c_layout) Array1.t)
(py : (float, float64_elt, c_layout) Array1.t) np =
let i = ref 2 in
let m = ref 1 in
while (!i < np) do
i := !i + !i;
m := !m + 1
done;
let n = !i in
if n <> np then begin
for i = np+1 to n do
px.{i} <- 0.0;
py.{i} <- 0.0
done;
print_string "Use "; print_int n;
print_string " point fft"; print_newline()
end;
let n2 = ref(n+n) in
for k = 1 to !m-1 do
n2 := !n2 / 2;
let n4 = !n2 / 4 in
let e = tpi /. float !n2 in
for j = 1 to n4 do
let a = e *. float(j - 1) in
let a3 = 3.0 *. a in
let cc1 = cos(a) in
let ss1 = sin(a) in
let cc3 = cos(a3) in
let ss3 = sin(a3) in
let is = ref j in
let id = ref(2 * !n2) in
while !is < n do
let i0r = ref !is in
while !i0r < n do
let i0 = !i0r in
let i1 = i0 + n4 in
let i2 = i1 + n4 in
let i3 = i2 + n4 in
let r1 = px.{i0} -. px.{i2} in
px.{i0} <- px.{i0} +. px.{i2};
let r2 = px.{i1} -. px.{i3} in
px.{i1} <- px.{i1} +. px.{i3};
let s1 = py.{i0} -. py.{i2} in
py.{i0} <- py.{i0} +. py.{i2};
let s2 = py.{i1} -. py.{i3} in
py.{i1} <- py.{i1} +. py.{i3};
let s3 = r1 -. s2 in
let r1 = r1 +. s2 in
let s2 = r2 -. s1 in
let r2 = r2 +. s1 in
px.{i2} <- r1*.cc1 -. s2*.ss1;
py.{i2} <- -.s2*.cc1 -. r1*.ss1;
px.{i3} <- s3*.cc3 +. r2*.ss3;
py.{i3} <- r2*.cc3 -. s3*.ss3;
i0r := i0 + !id
done;
is := 2 * !id - !n2 + j;
id := 4 * !id
done
done
done;
(************************************)
(* Last stage, length=2 butterfly *)
(************************************)
let is = ref 1 in
let id = ref 4 in
while !is < n do
let i0r = ref !is in
while !i0r <= n do
let i0 = !i0r in
let i1 = i0 + 1 in
let r1 = px.{i0} in
px.{i0} <- r1 +. px.{i1};
px.{i1} <- r1 -. px.{i1};
let r1 = py.{i0} in
py.{i0} <- r1 +. py.{i1};
py.{i1} <- r1 -. py.{i1};
i0r := i0 + !id
done;
is := 2 * !id - 1;
id := 4 * !id
done;
(*************************)
(* Bit reverse counter *)
(*************************)
let j = ref 1 in
for i = 1 to n - 1 do
if i < !j then begin
let xt = px.{!j} in
px.{!j} <- px.{i};
px.{i} <- xt;
let xt = py.{!j} in
py.{!j} <- py.{i};
py.{i} <- xt
end;
let k = ref(n / 2) in
while !k < !j do
j := !j - !k;
k := !k / 2
done;
j := !j + !k
done;
n
let test np =
print_int np; print_string "... "; flush stdout;
let enp = float np in
let npm = np / 2 - 1 in
let pxr = Array1.create float64 c_layout (np+2)
and pxi = Array1.create float64 c_layout (np+2) in
let t = pi /. enp in
pxr.{1} <- (enp -. 1.0) *. 0.5;
pxi.{1} <- 0.0;
let n2 = np / 2 in
pxr.{n2+1} <- -0.5;
pxi.{n2+1} <- 0.0;
for i = 1 to npm do
let j = np - i in
pxr.{i+1} <- -0.5;
pxr.{j+1} <- -0.5;
let z = t *. float i in
let y = -0.5 *. (cos(z)/.sin(z)) in
pxi.{i+1} <- y;
pxi.{j+1} <- -.y
done;
(**
print_newline();
for i=0 to 15 do Printf.printf "%d %f %f\n" i pxr.{i+1} pxi.{i+1} done;
**)
let _ = fft pxr pxi np in
(**
for i=0 to 15 do Printf.printf "%d %f %f\n" i pxr.{i+1} pxi.{i+1} done;
**)
let zr = ref 0.0 in
let zi = ref 0.0 in
let kr = ref 0 in
let ki = ref 0 in
for i = 0 to np-1 do
let a = abs_float(pxr.{i+1} -. float i) in
if !zr < a then begin
zr := a;
kr := i
end;
let a = abs_float(pxi.{i+1}) in
if !zi < a then begin
zi := a;
ki := i
end
done;
let zm = if abs_float !zr < abs_float !zi then !zi else !zr in
print_float zm; print_newline()
let _ =
let np = ref 16 in for i = 1 to 13 do test !np; np := !np*2 done